Math Help with i = mod 2, why?

[jb skaggs]

I am following chess tutorial for GM. My question is concerning the following code:

inside of the for loop to create the chess board is this little piece of math.

if ((i mod 2==0 && j mod 2==0) || (i mod 2 ==1 && j mod 2 ==1))

What specifically is happening here?

thanks JB

 

[Musehill]

if both i and j are even numbers -OR- both i and j are odd numbers, the following code will run. I haven't seen the tutorial, but maybe that will help you figure it out. Ii would guess it determines whether to place a black or white square?

 

[SyntaxError]

Esentially, (Im probably stating the obvious but...)
If (the remainder of i divided by 2 is equal to 0 and the remainder of j divided by 2 is equal to 0) is true or (the remainder of i divided by 2 equals 1 and the remainder of j divided by 2 equals 1) is true then...

Does that clear it up?

 

[JFitch]

This can be simplified to:

if (i+j) mod 2 == 0
{
}

assuming that i and j are both integers.

 

[jb skaggs]

thanks all.